{"id":393,"date":"2005-11-03T15:30:49","date_gmt":"2005-11-03T07:30:49","guid":{"rendered":"http:\/\/www.nargalzius.com\/blog2\/http:\/www.nargalzius.com\/blog2\/archives\/2005\/11\/2005_11_03_1530.php"},"modified":"2005-11-03T15:30:49","modified_gmt":"2005-11-03T07:30:49","slug":"top-2-percent","status":"publish","type":"post","link":"http:\/\/nargalzius.com\/blog\/archives\/2005\/11\/03\/top-2-percent","title":{"rendered":"Top 2 percent"},"content":{"rendered":"<p>Got this from <a href=\"http:\/\/www.livejournal.com\/~miye\" title=\"Visit blog\">Jem<\/a>, and answered it too. But I&#8217;m posting my solution here because when I googled to check if I got it right, I saw much simpler\/faster ways to answer it hahaha which made me kinda sad that I took a <em>&#8220;logical-long-cut.&#8221;<\/em> But nonetheless, it was nice to know that I solved it either way.<\/p>\n<blockquote>\n<p>Are you in the TOP 2% of intelligent people in the world? Solve the riddle and find out.\nThere are no tricks, just pure logic. So goodluck and don&#8217;t give up.<\/p>\n<ol>\n<li>In a street there are five houses, painted five different colors.<\/li>\n<li>In each house lives a person of different nationality.<\/li>\n<li>These five homeowners each drink a different kind of beverage, smoke different brand of cigar and keep a different pet.<\/li>\n<\/ol>\n<p>QUESTION: <strong>WHO OWNS THE FISH?<\/strong><\/p>\n<p>Hints:<\/p>\n<ol>\n<li>The Brit lives in a red house.<\/li>\n<li>The Swede keeps dogs as pets.<\/li>\n<li>The Dane drinks tea.<\/li>\n<li>The Green house is on the left of the White house.<\/li>\n<li>The owner of the Green house drinks coffee.<\/li>\n<li>The person who smokes Pall Mall rears birds.<\/li>\n<li>The owner of the Yellow house smokes Dunhill.<\/li>\n<li>The man living in the center house drinks milk.<\/li>\n<li>The Norwegian lives in the first house.<\/li>\n<li>The man who smokes Blends lives next to the man who keeps cats.<\/li>\n<li>The man who keeps horses lives next to the man who smokes Dunhill.<\/li>\n<li>The man who smokes Blue Master drinks beer.<\/li>\n<li>The German smokes Prince.<\/li>\n<li>The Norwegian lives next to the Blue house.<\/li>\n<li>The man who smokes Blends has a neighbor who drinks water.<\/li>\n<\/ol>\n<p>Albert Einstein wrote this riddle during the 19th century. He said that 98% of the population would not be able to solve it.<\/p>\n<\/blockquote>\n<!--more-->\n<p>My method was to represent each house, and list down <strong>all possibilities<\/strong> in each house&#8230; and do a process of elimination. But I would have to say that the <a href=\"http:\/\/www.frontiernet.net\/~mwdaly\/recpuzzles\/einstein.html\" title=\"Better solution\">solution I found in Google<\/a> after the excercise, was a faster and more elegant attack on the problem.<\/p>\n<p>Though my method was far from efficient, I guess I could find solace in the fact that I thought <em>out of the box<\/em> hahaha.<\/p>\n<hr \/>\n<p>In my method, after filling up the &#8220;possibilities&#8221; from the conditions on all 5 houses, and got something that looked like <a href=\"http:\/\/www.nargalzius.com\/blog\/archives\/images\/thumbs\/einstein_puzzle.gif\">this<\/a>. The little letter prefixes on some &#8220;possibilities&#8221; are only indicators &#8211; so when I eliminate something that is paired with another condition, I won&#8217;t forget to delete it&#8217;s &#8220;partner.&#8221;<\/p>\n<p>Getting right to it, you&#8217;ll notice that Conditions 9 and 13 forces the Norwegian and German to be distinct entries, just like the others <span class=\"footnote_referrer\"><a role=\"button\" tabindex=\"0\" onclick=\"footnote_moveToReference_393_1('footnote_plugin_reference_393_1_1');\" onkeypress=\"footnote_moveToReference_393_1('footnote_plugin_reference_393_1_1');\" ><sup id=\"footnote_plugin_tooltip_393_1_1\" class=\"footnote_plugin_tooltip_text\">1 <\/sup><\/a><span id=\"footnote_plugin_tooltip_text_393_1_1\" class=\"footnote_tooltip\">Now, since we have 5 distinct values in 1 common field (nationality) we can use that as identifiers as we go along.<\/span><\/span><script type=\"text\/javascript\"> jQuery('#footnote_plugin_tooltip_393_1_1').tooltip({ tip: '#footnote_plugin_tooltip_text_393_1_1', tipClass: 'footnote_tooltip', effect: 'fade', predelay: 0, fadeInSpeed: 200, delay: 400, fadeOutSpeed: 200, position: 'top right', relative: true, offset: [10, 10], });<\/script>. Furthermore, the <code>GERMAN\/PRINCE<\/code> pair eliminates the other cigars from the German&#8217;s entry&#8230; namely: <code>BEER\/BLUEMASTER<\/code>, <code>YELLOW\/DUNHILL<\/code>, <code>BIRDS\/PALLMALL<\/code>, and <code>BLENDS<\/code><\/p>\n<p>Condition 14 states that the second house should be blue &#8211; the German, Dane and the Swede are now in the running for the 2nd house.<\/p>\n<p>Condition 4 and 14 make it impossible for the Norwegian&#8217;s house to be blue, green, or white. It could&#8217;ve been green <em>if<\/em> the 2nd was white, which it <em>can&#8217;t<\/em> be (blue remember?). Eliminating the <code>BLUE<\/code>, <code>GREEN<\/code>, and <code>WHITE<\/code> adds <code>YELLOW\/DUNHILL<\/code> as the Norwegians fixed values.<\/p>\n<p>We now take out the extraneous relationships <code>GREEN\/COFFEE<\/code>, <code>BIRDS\/PALLMALL<\/code>, <code>BEER\/BLUEMASTER<\/code>, and <code>BLENDS<\/code>. Also, take out <code>YELLOW\/DUNHILL<\/code> from everyone else.<\/p>\n<p>Condition 8 allows us to take milk out from the Norwegian Dude&#8230; which leaves him with <code>WATER<\/code> &#8211; and in turn eliminates it from everyone else.<\/p>\n<p>Condition 15 allows us to eliminate <code>BLUE<\/code> from the German, and eliminate him altogether as a possible 2nd house &#8211; because it says the man who smokes Blends should be beside the Norwegian water-drinker.<\/p>\n<p>We also know that of the three (German, Dane and Swede), they could also be green or white, therefore 2 of the three <em>have to be<\/em> adjacent. This puts the Brit (RED) either as the center or the last house. If you notice, the 2 possible milk drinkers left are the Swede and the Brit, so the German is now solidified as the 4th house.<\/p>\n<p>The reason for such logic is that the possible permutations are:<\/p>\n<ol>\n<li><code>SWEDE<\/code> as <code>BLUE<\/code>, <code>BRIT<\/code> as center, <code>GERMAN<\/code> as <code>GREEN<\/code>, and <code>DANE<\/code> as <code>WHITE<\/code> last<\/li>\n<li><code>DANE<\/code> as <code>BLUE<\/code>, <code>BRIT<\/code> as center, <code>GERMAN<\/code> as <code>GREEN<\/code>, <code>SWEDE<\/code> as <code>WHITE<\/code> last<\/li>\n<li><code>DANE<\/code> as <code>BLUE<\/code>, <code>SWEDE<\/code> as <code>GREEN<\/code> center, <code>GERMAN<\/code> as <code>WHITE<\/code>, and <code>BRIT<\/code> as last<\/li>\n<\/ol>\n<p>The Dane can never be the center house since he ain&#8217;t a milk drinker, nor can he be green. So the 4th permutation of <code>SWEDE<\/code> as <code>BLUE<\/code>, <code>DANE<\/code> as <code>GREEN<\/code> center <code>GERMAN<\/code> as <code>WHITE<\/code> and <code>BRIT<\/code> as last &#8211; will <strong>not<\/strong> work.<\/p>\n<p>We also know that the BLUE house is the man with horses, because the man that smokes Dunhill is already the first house (condition 11) &#8211; so the Swede&#8217;s pet dogs will <strong>not<\/strong> allow him to be the blue house. Having said that, the Dane is now the blue, house with horses for certain! So take out <code>WHITE<\/code>, <code>CATS<\/code>, <code>FISH<\/code>, and <code>BIRDS\/PALMALL<\/code> from the Dane &#8211; and we&#8217;re now left with a person who smokes <code>BLENDS<\/code>.<\/p>\n<p>You&#8217;d notice at this point, only <em>one person<\/em> can possibly be a <code>BLUEMASTER\/BEER<\/code> smoker\/drinker (Swede), so we can now delete <code>GREEN\/COFFEE<\/code> and <code>MILK<\/code> from the Swede (making his house <code>WHITE<\/code> in the process)<\/p>\n<p>If we eliminate <code>BLUEMASTER<\/code> from the rest, then we see the Brit as a <code>PALMALL<\/code> smoking, <code>BIRD<\/code> owner (taking condition 6 into account). Not only that, it leaves the Brit as the milk drinker &#8211; ergo the center house.<\/p>\n<p>I guess condition 10 was talking about the Norwegian as the cat-dude.<\/p>\n<p>So we take out <code>CATS<\/code>, <code>HORSES<\/code>, <code>FISH<\/code> from the Brit&#8230; and <code>HORSES<\/code> and <code>FISH<\/code> from the Norwegian.<\/p>\n<p>And since we have derived enough to finish the process of cross-elimination, we can see that the Swede <strong>has<\/strong> to be the last, <em>white,<\/em> house for the German GREEN house to be on its left.<\/p>\n<p>Houses are now:<\/p>\n<ol>\n<li>NORWEGIAN\/YELLOW\/CATS\/WATER\/DUNHILL<\/li>\n<li>DANE\/BLUE\/HORSES\/TEA\/BLENDS<\/li>\n<li>BRIT\/RED\/BIRDS\/MILK\/PALLMALL<\/li>\n<li>GERMAN\/GREEN\/FISH\/COFFEE\/PRINCE<\/li>\n<li>SWEDE\/WHITE\/DOGS\/BEER\/BLUEMASTER<\/li>\n<\/ol>\n<p>So my final answer is: the NAZI owns the fish!<\/p><div class=\"speaker-mute footnotes_reference_container\"> <div class=\"footnote_container_prepare\"><p><span role=\"button\" tabindex=\"0\" class=\"footnote_reference_container_label pointer\" onclick=\"footnote_expand_collapse_reference_container_393_1();\">Notes<\/span><span role=\"button\" tabindex=\"0\" class=\"footnote_reference_container_collapse_button\" style=\"display: none;\" onclick=\"footnote_expand_collapse_reference_container_393_1();\">[<a id=\"footnote_reference_container_collapse_button_393_1\">+<\/a>]<\/span><\/p><\/div> <div id=\"footnote_references_container_393_1\" style=\"\"><table class=\"footnotes_table footnote-reference-container\"><caption class=\"accessibility\">Notes<\/caption> <tbody> \r\n\r\n<tr class=\"footnotes_plugin_reference_row\"> <th scope=\"row\" class=\"footnote_plugin_index_combi pointer\"  onclick=\"footnote_moveToAnchor_393_1('footnote_plugin_tooltip_393_1_1');\"><a id=\"footnote_plugin_reference_393_1_1\" class=\"footnote_backlink\"><span class=\"footnote_index_arrow\">&#8673;<\/span>1<\/a><\/th> <td class=\"footnote_plugin_text\">Now, since we have 5 distinct values in 1 common field (nationality) we can use that as identifiers as we go along.<\/td><\/tr>\r\n\r\n <\/tbody> <\/table> <\/div><\/div><script type=\"text\/javascript\"> function footnote_expand_reference_container_393_1() { jQuery('#footnote_references_container_393_1').show(); jQuery('#footnote_reference_container_collapse_button_393_1').text('\u2212'); } function footnote_collapse_reference_container_393_1() { jQuery('#footnote_references_container_393_1').hide(); jQuery('#footnote_reference_container_collapse_button_393_1').text('+'); } function footnote_expand_collapse_reference_container_393_1() { if (jQuery('#footnote_references_container_393_1').is(':hidden')) { footnote_expand_reference_container_393_1(); } else { footnote_collapse_reference_container_393_1(); } } function footnote_moveToReference_393_1(p_str_TargetID) { footnote_expand_reference_container_393_1(); var l_obj_Target = jQuery('#' + p_str_TargetID); if (l_obj_Target.length) { jQuery( 'html, body' ).delay( 0 ); jQuery('html, body').animate({ scrollTop: l_obj_Target.offset().top - window.innerHeight * 0.2 }, 380); } } function footnote_moveToAnchor_393_1(p_str_TargetID) { footnote_expand_reference_container_393_1(); var l_obj_Target = jQuery('#' + p_str_TargetID); if (l_obj_Target.length) { jQuery( 'html, body' ).delay( 0 ); jQuery('html, body').animate({ scrollTop: l_obj_Target.offset().top - window.innerHeight * 0.2 }, 380); } }<\/script>","protected":false},"excerpt":{"rendered":"<p>Got this from Jem, and answered it too. But I&#8217;m posting my solution here because when I googled to check if I got it right, I saw much simpler\/faster ways to answer it hahaha which made me kinda sad that I took a &#8220;logical-long-cut.&#8221; But nonetheless, it was nice to know that I solved it &hellip; <p class=\"link-more\"><a href=\"http:\/\/nargalzius.com\/blog\/archives\/2005\/11\/03\/top-2-percent\" class=\"more-link\">Continue reading<span class=\"screen-reader-text\"> &#8220;Top 2 percent&#8221;<\/span><\/a><\/p><\/p>","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","enabled":false},"version":2}},"categories":[10],"tags":[970],"class_list":["post-393","post","type-post","status-publish","format-standard","hentry","category-nonsense","tag-puzzle"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"jetpack-related-posts":[],"_links":{"self":[{"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/posts\/393","targetHints":{"allow":["GET"]}}],"collection":[{"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/comments?post=393"}],"version-history":[{"count":0,"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/posts\/393\/revisions"}],"wp:attachment":[{"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/media?parent=393"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/categories?post=393"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/nargalzius.com\/blog\/wp-json\/wp\/v2\/tags?post=393"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}